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Replies:
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Last Post:
Nov 30, 2009 1:21 PM
by: Jon Reider
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Posts:
31
Registered:
3/16/09
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memberships of all users in an ou
Posted:
Nov 25, 2009 12:56 PM
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I have a script that will list all users memberships in an OU, but I don't know what user belongs to what groups. My list looks like:
I would like these groups to be separated by each user.
Name ---- 126_MyLeads_Email Cancun 2009 126_ShipNotify 126_Supports 126_SalesActivity 126_Arkoma 126 126_MyLeads_Email Cancun 2009 Reps - Domestic - Principals Reps - Bryan - Principals Incentive Trip - March 126_ShipNotify 126_SalesActivity 126_Arkoma 126 Reps - West - Principals 126_Principals 126_MyLeads_Email 126_ShipNotify 126_Supports 126_SalesActivity 126_Arkoma 126 126_MyLeads_Email Cancun 2009 126_InternationalShipping 126_SalesOrderAcknowledgement 126_ShipNotify Repnet Testers 126_Supports 126_SalesActivity 126_Arkoma 126 PlayCADusers
$RepNo = Read-Host -Prompt "Enter Rep Number"
# Looks for any OU with the name you put in the prompt $RepName = get-qadobject -Type OrganizationalUnit | select Name | Where-Object {$_.Name -like "$RepNo*"} # Cleans up the name attribute so it can be used as an OU. $RepNamefix = $RepName -replace "@{Name=","" -replace "}","" # Puts the name in OU format $RepOU = "ou=" + $RepNamefix + ",ou=reps,dc=playlsi,dc=com" # Gets all users in an OU $User = Get-QADUser -SearchRoot $RepOU -SearchScope OneLevel ForEach ($members in $user){ $members.memberOf | Get-QADGroup | sort }
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Posts:
414
Registered:
12/15/08
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Re: memberships of all users in an ou
Posted:
Nov 30, 2009 12:45 PM
in response to: Jon Reider
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Answered |
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Hi John,
If I understand you correctly, I think you can get what you want by changing your last foreach statement to this:
ForEach ($members in $user){ $members.Name "-----------------" $members.memberOf | Get-QADGroup | sort | foreach{$_.name} "" }
It will print the user's name followed by some dashes, followed by the names of the groups that the user is a member of.
-Chris
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Posts:
31
Registered:
3/16/09
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Re: memberships of all users in an ou
Posted:
Nov 30, 2009 1:21 PM
in response to: seaJhawk
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Perfect and simple.
Thanks again SeaJhawk.
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